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(1/6)^3x=36
We move all terms to the left:
(1/6)^3x-(36)=0
Domain of the equation: 6)^3x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/6)^3x-36=0
We multiply all the terms by the denominator
(+1-36*6)^3x=0
We add all the numbers together, and all the variables
(-215)^3x=0
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